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Re: Discutii libere

Posted: Wed Oct 17, 2012 10:55 pm
by StreetKiller
Se cere numele pentru a da rewarduri la playeri daca acestia voteaza (atata timp cat este pus pluginul corespunzator)
Nu e acolo pentru a verifica daca contul e premium sau nu :|
P.S. Scrie si mai jos de campul pentru Minecraft Username
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Re: Discutii libere

Posted: Thu Oct 18, 2012 2:49 pm
by Name
Thank you for voting today, Name!
Please come back in 17 hours to vote again.

Re: Discutii libere

Posted: Wed Oct 24, 2012 5:50 pm
by DeenzHD
Salut, particip la un fel de concurs si mi s-a dat sa decodez/decriptez un anumit text sa trec mai departe... textul este:
GTAZMMQINLAYGEJLWDUSHMFPIKHSIWREDVANVIKBEGAWEQSJTETENLQHQAJRMWAVMGTUAJBEJEFLQGGFFNLSIGHMLIECEBDNRIEEQTYXKTSFTYWQAJRNTAFRGZMIKHZXAFBYMQSJRMJFBNFVUTFNRLEYEVGZEGFKTTUXEWESRZCTAFRHWMSPHFPIGHTAMSZZSTSFRGMROLGBXTBNLOQLCWMCECFEWFHVFCHSNZWWMSPICPSLHZSUTFUGPSVZMWESPHSUOHGVAFOLMUTLYWGFQPDFCIHRFWKEAXXCPSLIWSEYFAYXTBUASEIXNCHSLHMXAUEWGIOHMOWXLUHLTPZFWLTEDXQHATXWSEYGXYHYBASAFOSBYHITNWKEYFNDDUAWALAUKPCALQHFWBMDXRWEZXKKMGVXYHYCXSKKOYTGIOOBSKUGLXQHYBNXGGNUBRDUGPWDXDFGCEMZXLZQMVLQPGRXSKKPVTQNOUTALABZTQXGHXKKKOLYMJNQBLGGTNXJADBGWHYMVMFTMRLKSSEVTQNPRTKQAHRBRDBVTKASUVLQNOHYGMZDZMMJTJXDDPOEXNBMRMZWYEJLYVERTKQBERLW


Ca indiciu am primit:
the encryption method used dates from the 15th century..
In Romana:
Metoda de criptate foloseste date din al 15-lea secol.

Ma paote ajuta cineva? :S

Re: Discutii libere

Posted: Wed Oct 24, 2012 6:03 pm
by StreetKiller
Pai , cred ca te pot ajuta eu..
In primul rand ai tradus prost in romana
indiciul primit de tine inseamna Metoda de criptare este una din secolul 15
Pai acolo ai o harababura totala..
Nu sunt sigur dar am impresia ca stiu metoda de criptare.
Mie cam greu sa explic but whatever.
Fiecare litera e schimbata cu o alta litera din alfabet dupa o regula
De exemplu A devine D , B devine E si tot asa.
pe scurt ar putea fi ceva de genul , inlocuieste fiecare litera cu alta cu n pozitii mai la dreapta in alfabet. (n<26)
Pana cand trebuie sa rezolvi asta?

Re: Discutii libere

Posted: Wed Oct 24, 2012 6:18 pm
by DeenzHD
Cat mai rapid. E un fel de concurs care rezolva primul 10 puzzle-uri. Sunt realizate doar 6 puzzle-uri momentan. Asta ar fi al 4-lea puzzle. Primele 3 le-am rezolvat singur. Toate sunt chestii din astea care trebuie decriptate. Nu stiu exact cat va dura pana va termina cineva, deocamdata nu a trecut nimeni de 5.

Re: Discutii libere

Posted: Wed Oct 24, 2012 6:32 pm
by StreetKiller
Daca trebuie lucrat la asta inca de acum nu prea am timp sa te ajut ...
Incearca sa decalezi fiecare litera din alfabet cu un numar mai mic sau egal cu 25
De exemplu daca numarul pe care il alegi e 3 o sa schimbi in propozitia ta D cu A , E cu B , F cu C si tot asa.
Daca nu iti iese nimic incearca sa cauti pe google metode de criptare si vezi daca gasesti una folosita si in sec 15

Re: Discutii libere

Posted: Wed Oct 24, 2012 6:35 pm
by DeenzHD
Am incercat si cum ai zis tu si am incercat si aia cu metodele de crpitare... Am gasit ceva cu Cesar Cipher care e exact ce ai zis tu. Alt ceva nu am mai gasit...

Tu incearca totusi cand ai timp sa o faci, anunt eu daca se termina concursul intre timp. Voi mai incerca si eu ce pot :S

Re: Discutii libere

Posted: Wed Oct 24, 2012 9:22 pm
by Alex
e interesanta criptarea...dar spatii nu are?

Re: Discutii libere

Posted: Thu Oct 25, 2012 5:21 pm
by DeenzHD
Mi s-a dat urmatorul:

I hashed a piece of text (called plaintext) and from that I got the hash:
Message Digest (MD5): 3de5c081630b4c2f114b1b8b42e9ff36

Hint: The plaintext matches the regular expression [(a|d|l)n-t\|]{8}

Find out how to crack an md5 (can't be done online) and use the regular expression to crack it in 10 seconds instead of 10 days..

Question: what's the plaintext I used?

Re: Discutii libere

Posted: Thu Oct 25, 2012 5:33 pm
by Cbla
ce urasc regex (expresiile regulate)
[(a|d|l)n-t\|]{8}
daca imi amintesc inseamna (dar pune mana pe google si citeste regular expressions), {8}cred ca inseamna ca expresia de inainte se repeta de 8 ori.
iar expresia de inainte inseamna:
(a|d|l) = a sau d sau l (litere)
apoi urmeaza o litera intre n si t (din alfabet) si pe urma o bara "|"
si toate asta de 8 ori, deci generezi combinatiile posibile (nu sunt multe) si calculezi md5 pentru ei pana gasesti cel potrivit.

Re: Discutii libere

Posted: Thu Oct 25, 2012 7:25 pm
by DeenzHD
Pai pana acum am cautat pe google si am incercat sa inteleg insa nu m-am prea prins. Am inteles ca e legat de programare sau ceva de genul insa chestia aia cu MD5 nu stiu ce e :S

dar sa vad daca ai inteles. Expresia de mai sus desfacuta ar veni ceva de genul:
an|dn|ao|ln|dt|do|at| etc...?
Daca e bine fac toate combinatiile posibile?

Edit am gasit un fel de cracker online.
http://www.md5decrypter.co.uk/
L-am folosit si mi-o dat chestia asta:
3de5c081630b4c2f114b1b8b42e9ff36 MD5: not|lard
deci ar fi not|lard . La sta ce mai trebuie sa-i fac? :o

edit2: not|lard era corect. Multumesc @cbla pentru ajutor. Nu ma descurcam fara tine.


L-am primit pe urmatorul, asta e mai incurcat aparent..

Decode the list to get two hex values, both 8 characters long

Input Output
7f6d = ?
b0e0 = ?
f66e =?
6c1a =?
06ec =?
3948 =?
9158 =?
c7e9 =?

ecb8 =?
dbb5 =?
de7b =?
3af6 =?
c3eb =?
ed4b =?
0ea9 =?
a472 =?

Use the example below to figure the encoding/decoding that's going on

Input Output
0 0
1 1
2 2
3 3
4 4
5 5
6 6
7 7
8 8
9 9
a a
b b
c c
d d
e 0
f 1
ff 2
fff 3
ffff 4

Instead of telling you what to do with it, here is some pseudo code!

h1 = xxxxxxxx; // which you got from the first part of the puzzle
h2 = xxxxxxxx; // which you got from the first part of the puzzle

b1 = bxor(h1, h2);
b2 = subtractBit(b1, '11100111111001111000100000000000');

b3 = bxor(b2, '11111110000');

i1 = binToInt(b3);

sendPM('Jonas Brooke', h1, h2, b1, b2, b3, i1);

Okay here is a hint to get you guys started xD

First thing you need to do, is figure out the function you should use to get the output from a certain input.
Use the example for this.

If you have no fookin' clue [what's going on inside the function] then think about a clock. If it's 0:00 now and I wait 20 hours it will be 20:00 hours. But if it is 0:00 and I wait 30 hours, it will be 06:00 (and not 30:00 ) Apparently, after 24 hours the time will "reset" back to 0:00, in other words, it's a cycle. *cough* remainder after division *cough*

If you look closely to the input and output (ignore last 3 rows) you will notice something similiar to a clock/the time is happening. But these are not hours and the cycle doesn't end at 24..

Input Output
0 0
1 1
2 2
3 3
4 4
5 5
6 6
7 7
8 8
9 9
a a
b b
c c
d d
e 0
f 1
ff 2
fff 3
ffff 4

Now about the last 3 rows, [in these] there are multiple characters instead of only 1 (ff, fff, ffff). So how do you deal with that? Well first look at the output that comes from it, and try to figure out what's going on.

total = 0;
foreach characters as char {
total = total + char[value];
}
output = total % intTohex(14);

Here's the first three answers, so you can check if you're doing it allright.

7f6d d
b0e0 b
f66e d

Re: Discutii libere

Posted: Tue Nov 20, 2012 3:56 pm
by k3nZz0r
Happy Bday Name :yay: :hbd: :yay:

Re: Discutii libere

Posted: Tue Nov 20, 2012 10:27 pm
by Name
Sa fie primit!

Condoleante

Re: Discutii libere

Posted: Fri Nov 30, 2012 5:25 pm
by Doggy
La multi ani Garny :hbd: :hbd:

Re: Discutii libere

Posted: Fri Nov 30, 2012 5:37 pm
by Garnyatar
Ms ms :rabbit: :rabbit: :rabbit: